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An electron is accelerated through a potential difference of 100 volts. What is the de-Broglie wavelength associated with it? To which part of the electromagnetic spectrum does this value of wavelength correspond ?

Text Solution

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`lambda=(h)/(sqrt(2meV))` or `lambda=(12.27)/(sqrtV)` Å
`lambda=(12.27)/(sqrt100)Å=1.227Å`
This wavelength corresponds to the X-rays.
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