Home
Class 12
PHYSICS
A given coin has a mass of 3.0g . Calcul...

A given coin has a mass of 3.0g . Calculate the nuclear energy that would be required to separate all the neutrons and protons from each other . For simplicity, assume that the coin is entirely made of `._(29)^(63)Cu` atoms (of mass 62.92960 u)

Text Solution

Verified by Experts

Mass defect in each copper nucleus
`Delta m = 29 m_(p) + 34 m_(n) - M_(Cu)`
`= (29 xx 1.00727 ) + (34 xx 1.00866) -62.929 60`
`Delta m = 0.57567` u
Energy required to separate all neutrons and protons in one nucleus (is binding energy)
`= Delta m xx 931.5 "MeV"`
`E_(b) = 0.57567 x 931.5 = 536.2 "MeV"`
Number of atoms in the copper coin :
`N= (6.023 xx 10^(23) xx 3)/( 63) = 2.868 xx 10^(22)`
`therefore` Total energy required to separate all neutrons and protons in the coin
`E_(b) xx N `
`536.2 xx 2.868 xx 10^(22) = 1.538 xx 10^(25) "MeV"` (with unit)
Promotional Banner

Topper's Solved these Questions

  • NUCLEI

    OSWAAL PUBLICATION|Exercise TOPIC -2 (Very Short Answer Type Questions)|5 Videos

  • NUCLEI

    OSWAAL PUBLICATION|Exercise TOPIC -2 (Short Answer Type Questions-I)|2 Videos

  • NUCLEI

    OSWAAL PUBLICATION|Exercise TOPIC -1 (Long Answer Type Questions-I)|3 Videos

  • MOVING CHARGES & MAGNETISM

    OSWAAL PUBLICATION|Exercise TOPIC-3 (Current Carrying Conductor & Galvanometer) (Numerical Problem)|1 Videos

  • RAY OPTICS AND OPTICAL INSTRUMENTS

    OSWAAL PUBLICATION|Exercise TOPIC-3(Numerical Problems)|3 Videos

Similar Questions

Explore conceptually related problems

A copper coin has a mass of 63.0g. Calculate the nuclear energy that would be required to separate all the neutrons and protons form each other. The coin is entirely made of ""_(29)^(63)Cu atoms. Mass of ""_(29)^(63)Cu atom = 62.92960u mass of proton = 1.00727u Mass of neutron = 1.00866u Avogadro's number = 6.022 xx 10^(23)

Ten one-rupee coins are put on top of each other on a table. Each coin has a mass m. Give the magnitude and direction of (a) the force on the 7th coin (counted from the bottom) due to all the coins on its top, (b) the force on the 7th coin by the eighth coin, (c) the reaction of the 6th coin on the 7th coin

A thermal neutron strikes U_(92)^(235) nucleus to produce fission. The nuclear reaction is as given below : n_(0)^(1) + U_(92)^(235) to Ba_(56)^(141) + Kr_(36)^(92) +3n_(0)^(1) + E Calculate the energy released in MeV. Hence calculate the total energy released in the fission of 1 Kg of U_(92)^(235) . Given mass of U_(92)^(235) = 235.043933 amu Mass of neutron n_(0)^(1) =1.008665 amu Mass of Ba_(56)^(141)=140.917700 amu Mass of Kr_(36)^(92)=91.895400 amu

An element having atomic mass 63.1 g/mol has face centered cubic unit cell with edge length 3.608 xx 10^(-8) cm. Calculate the density of unit cell [Given N_(A) = 6.022 xx 10^(23) atoms/mol].