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A heavy nucleus X of mass number 240 and...

A heavy nucleus X of mass number 240 and binding energy per nucleon 7.6 MeV is split into two fragments Y and Z of mass numbers 110 and 130. The binding energy of nucleons in Y and Z is 8.5 Me V per nucleon. Calculate the energy Q released per fission in Me V.

Text Solution

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`X^(240) to Y^(110) + Z^(130) + Q`
Energy released per nucleon `= 8.5 "MeV" -7.6 "MeV"`
`=0.9 "MeV"`
Therefore energy released `=0.9 xx 240`
`= 216 "MeV"`
Alternatively :
Energy released `= [240 xx 8.5 -7.6 (110 + 130) ] :"MeV"`
`=216 "MeV"`
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