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Show that 1 amu = 932 MeV....

Show that 1 amu = `932 MeV`.

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(i) The difference between the rest mass of a nucleus and the sum of the masses of its constituents is called Nuclear-mass defect.
(ii) The ratio of the Binding energy of a nucleus to the number of nucleons or Binding energy per nucleons, of a nucleus is called specific binding energy.
`E=mc^(2)`
Taking `m=1 amu=1.66 xx 10^(-27) ` kg
and `c=2.9979 xx 10^(8) ms^(-1)`
Also MeV `=1.6 xx 10^(-13) ` J
Arriving at ` amu `=931` MeV
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