Home
Class 12
PHYSICS
Calculate the energy released in the fol...

Calculate the energy released in the following nuclear reaction and hence calculate the energy released when 235 gram of uranium-235 undergoes fission.
`U_(92)^(235) + n_(0)^(1) to Kr_(36)^(92) + Ba_(56)^(141) + 3n_(0)^(1)`
Rest masses of `U^(235), Ba^(141) ,Kr^(92)` and neutron are 235.04390 amu, 140.91390 amu, 91.89730 amu and 1.00867 amu respectively. Avogadro number `= 6.023 xx 10^(23)`.

Text Solution

Verified by Experts

Sum of the masses of the reactants `=236.05257` amu
Sum of the masses of the products `=235.83721` amu
Mass converted to energy per fission `=0.215236` amu
Energy released per fission `=0.21536 xx 931`
`=200.50016` MeV
`200.5 xx 1.6 xx 10^(-13) = 3.208 xx 10^(-11)` J
Energy released when 235 gram of `U^(235)` undergoes fission
`=200.5 xx 6.023 xx 10^(23)`
`=1.2076 xx 10^(26)` MeV
or
`1.932 xx 10^(13)` J
Promotional Banner

Topper's Solved these Questions

  • NUCLEI

    OSWAAL PUBLICATION|Exercise TOPIC -2 (Long Answer Type Questions)|2 Videos

  • MOVING CHARGES & MAGNETISM

    OSWAAL PUBLICATION|Exercise TOPIC-3 (Current Carrying Conductor & Galvanometer) (Numerical Problem)|1 Videos

  • RAY OPTICS AND OPTICAL INSTRUMENTS

    OSWAAL PUBLICATION|Exercise TOPIC-3(Numerical Problems)|3 Videos

Similar Questions

Explore conceptually related problems

Calculate and compare the energy released by a) fusion of 1.0 kg of hydrogen deep within Sun and b) the fission of 1.0 kg of ""^(235)U in a fission reactor.

""_(92)^(235)U+nto""_(92)^(235)Uto fission product + Neutron 3.20xx10^(-11)J . The energy released when 1 g of ""_(92)^(235)U undergoes fission is

A thermal neutron strikes U_(92)^(235) nucleus to produce fission. The nuclear reaction is as given below : n_(0)^(1) + U_(92)^(235) to Ba_(56)^(141) + Kr_(36)^(92) +3n_(0)^(1) + E Calculate the energy released in MeV. Hence calculate the total energy released in the fission of 1 Kg of U_(92)^(235) . Given mass of U_(92)^(235) = 235.043933 amu Mass of neutron n_(0)^(1) =1.008665 amu Mass of Ba_(56)^(141)=140.917700 amu Mass of Kr_(36)^(92)=91.895400 amu

On neutron bombardment fragmentation of U-235 occurs according to the equation 92^(U^(235)) + 0^(n^(1)) rarr 42^(Mo^(95)) + 57^(La^(139)) + x_(-1)^(e^(0)) + y_(0)^(n^(1)) Calculate the values of x and y.

A copper coin has a mass of 63.0g. Calculate the nuclear energy that would be required to separate all the neutrons and protons form each other. The coin is entirely made of ""_(29)^(63)Cu atoms. Mass of ""_(29)^(63)Cu atom = 62.92960u mass of proton = 1.00727u Mass of neutron = 1.00866u Avogadro's number = 6.022 xx 10^(23)

Complete the following nuclear reactions (i) 18^(Ar^(40)) + ? rarr 19^(K^(40)) + 0^(n^(1)) (ii) ______ + 1^(H^(1))rarr 2^(He^(4)) + 2^(He^(4)) (iii) 88^(Ra^(236))rarr ? + 2^(He^(4)) (iv) 92A^(U^(238))rarr 56^(Ba^(143)) + _______+ 0^(n^(1))