Home
Class 12
PHYSICS
State Ampere's circuital law . Using it,...

State Ampere's circuital law . Using it, derive the expression for magnetic field at a point due to a long current carrying conductor .

Text Solution

Verified by Experts

Ampere.s circuital law: The integral of the product of magnetic field and length element is equal to Ho times the total current passing through the surface.
`oint vecB.vec(dl)=mu_0I`.

Consider a point at distance .r. from a straight infinite current carrying wire .
From Ampere.s circuital law `oint vecB.vec(dl)=B. 2pir=mu_0 I. `
`B=(mu_0I)/(2pir)`
Promotional Banner

Topper's Solved these Questions

  • II PUC MARCH-2018

    OSWAAL PUBLICATION|Exercise PART-D|11 Videos
  • II PUC MARCH-2018

    OSWAAL PUBLICATION|Exercise PART-B|8 Videos
  • II PUC MARCH-2017 (SOLVED PAPER )

    OSWAAL PUBLICATION|Exercise PART-D|11 Videos
  • KARNATAKA II PUC APRIL 2020 CLASS -XII

    OSWAAL PUBLICATION|Exercise PART-D (Answer any three of the following questions:)|5 Videos

Similar Questions

Explore conceptually related problems

Write the expression for the magnetic field at a point due to a current element.

Give the expression for magnetic flux density, at a point on the axis, due to a current carrying circular conductor.

Write the expression for magnetic field at the centre of a current carrying circular coil.

Write the expression for magnetic flux at one end of a long solenoid carrying current.

Derive the expression for magnetic field at a point on the axis of a circular current loop.