Home
Class 12
PHYSICS
Light of frequency 8.41xx10^(14)Hz is in...

Light of frequency `8.41xx10^(14)Hz` is incident on a metal surface. Electrons with their maximum speed of `7.5xx10^(5)ms^(-1)` are ejected from the surface. Calculate the threshold frequency for photoemission of electrons. Also find the work function of the metal in electron volt `(eV)`. Given Plank's constant `h=6.625xx10^(-34)Js` and mass of the electron `9.1xx10^(-31)kg`.

Text Solution

Verified by Experts

`K_(max)=hv-omega_0`
`hv=hv_0+1/2 mv^2`
`hv_0=(6.625xx10^(-34)xx8.41xx10^14)-1/2xx9.1xx10^(-31)xx(7.5xx10^5)^2`
Calculation of threhold frequently `v_0=4.54xx10^14` Hz
Work function , `omega_0=hv_0`
Work function , `omega_0=(6.625xx10^(-34)xx4.54xx10^14)/(1.6xx10^(-19))`
Work function , `omega_0`=1.88 eV
Promotional Banner

Topper's Solved these Questions

  • II PUC MARCH-2018

    OSWAAL PUBLICATION|Exercise PART-C|8 Videos

  • II PUC MARCH-2017 (SOLVED PAPER )

    OSWAAL PUBLICATION|Exercise PART-D|11 Videos

  • KARNATAKA II PUC APRIL 2020 CLASS -XII

    OSWAAL PUBLICATION|Exercise PART-D (Answer any three of the following questions:)|5 Videos

Similar Questions

Explore conceptually related problems

Light of frequency 7.21 xx 10^(14) Hz is incident on a metal surface. Electrons with a maximum speed of 6.0 xx 10^(5)m//s are ejected from the surface. What is the threshold frequency for photoemission of electrons?

Calculate the wavelength of an electron moving with a velocity of 2.5xx10^(-7) ms^(-1)h=6.626xx10^(-34)Js: mass of an electron= 9.11xx10^(-31) kg.

The deBroglie wavelength of an electron travelling at 1% of the speed of light is( h=6.6xx10^(-4) Js, mass of electron =9.0xx10^(-31) kg

A photon of frequency 1.5xx10^(15) Hz is incident on a metal surface of work function 1.672 eV. Calculate the stopping potential.

The threshold wavelength for the ejection of electron for metal X is 330 nm. The work function for photoelectric emission from metal X is (h=6.6xx10^(-34)Js)

In an atom, an electron is moving with a speed of 6200 m/s which the position of an electron can be locates is (h=6.6xx10^(-34)kgm^(2)s^(-1) , mass of electron e_(m)=9.1xx10^(-31)kg)

When light of frequency 6 xx 10^(14) Hz is incident on a photosensitive metal, the kinetic energy of the photoelectron ejected is 2e V. Calculate the kinetic energy of the photoelectron in eV when light to frequency 5 xx 10^(14) Hz is incident on the same metal. Given Planck's constant, h = 6.625 xx 10^(-34) Js , 1 eV = 1.6 xx 10^(-19) .

Calculate the uncertainty in the position of an electron if the uncertainty in its velocity is 5.7 xx 10^5 m//sec (h = 6.626 xx 10^(-34) kg m^2 s^(-1) , mass of the electron = 9.1 xx 10^(−31) kg ).