If the electric field is given by `vec(E ) = ((100)/(x^(2)))i` the potential difference between points x=10m and x=20m in volts is

Electric field at a distance x from the origin is given as E =(100N-m^2//C)/x^2 . Then potential difference between the points situated at x = 10 m and x = 20m is :-

Figure shows the variation of electric field intensity E with distance x. The potential difference between the point x = 0 and x= 5m is

Figure shows the variation of electric field intensity E versus distance x. The magnitude potential difference between the point at x = 0 to x = 6 m will be

An electric field is expressed as vec(E ) = hat(i)x + hat(k)z . What is the potential difference (in volt) between A(0,0,0) and B(2,2,0)?

Magnitude of electric field only on the x-coordinate as vec(E)=20/x^(2) hat(i) V//m . Find (i) The potential difference between two points A (5m, 0) and B (10m, 0). (ii) Potential at x = 5 if V at oo is 10 volt.

Magnitude of electric field only on the x-coordinate as vec(E)=20/x^(2) hat(i) V//m . Find (i) The potential difference between two points A (5m, 0) and B (10m, 0). (ii) Potential at x = 5 if V at oo is 10 volt. (iii) In part (i), does the potential difference between a and B depend on whether the potential at oo is 10 volt or something else.

An electric field is described as vec(E) = hat(i)x + hat(k) z . The potential difference V_(AB) (in volt) between A(0,0,0) and B(2,2,0) is :

A uniform electric field is along x-axis. The potential difference V_(A)-V_(B)=10 V is between two points A (2m, 3m) and (4m, 8m). Find the electric field intensity.