Home
Class 9
MATHS
In the given figure, line l is the bise...

In the given figure, line l is the bisector of an angle `angleA` and B is any point on l. If BP and BQ are perpendiculars from B to the arms of `angleA`, show that
(i) `DeltaAPB~=DeltaAQB`
(ii) BP = BQ, i.e., B is equidistant from the arms of `angleA`.

Promotional Banner

Similar Questions

Explore conceptually related problems

Line l is the bisector of an angle angleA and B is any point on l. BP and BQ are perpendiculars from B to the arms of angleA show that: triangleAPBequivtriangleAQB

Line l is the bisector of an angleA and B is any point on I. BP and BQ are perpendiculars from B to the arms of angleA (see figure). Show that: DeltaAPB~=DeltaAQB

line l is the bisector of an angle /_A\ a n d/_B is any point on l. BP and BQ are perpendiculars from B to the arms of /_A . Show that: (i) DeltaA P B~=DeltaA Q B (ii) BP = BQ or B is equidistant from the arms of /_A

Line l is the bisector of an angle angleA and B is any point on li. BP and BQ are perpendicular forms B to the arms of angleA . Show that: triangleAPB ~= triangleAQB (ii) BP = BQ or B is equidisitant from the arms of angleA .

Line l is the bisector of an angle angle A and B is any point on l. BP and BQ are perpendiculars from B to the arms of angle A (see Fig. 7.20). Show that: (i) triangle APB cong triangle AQB (ii) BP = BQ or B is equidistant from the arms of angle A .

Ray 1 is the bisector of an angle angle A and B is any point on I. BP and BQ are perpendiculars from B to the arms of angle A (see the given figure). Show that: (i) triangleAPB=triangleAQB (ii) BP = BQ or B is equidistant from the arms of angleA

In the given figure, line I is the bisector of an angle A and B is any point on I. BP and BQ are perpendiculars from B to the arms of angleA . Show that B is equidistant from the arms of angleA .

Line l is the bisector of an angle angleA and B is any point on l. BP and BQ are perpendiculars from B to the arms of angleA show that: BP=BQ or B is equidistant from the arms of angleA

In Figure, line l is the bisector of angle A and B is any point on l . B P and B Q are perpendiculars from B to the arms of Adot Show that : A P B~=A Q B B P=B Q or B is equidistant from the arms of /_A . Figure

In Figure, line l is the bisector of angle A and B is any point on l . B P and B Q are perpendiculars from B to the arms of Adot Show that : A P B~=A Q B B P=B Q or B is equidistant from the arms of /_A . Figure