Calculate the minimum speed required by a rocket to pull out of the gravitational force of Mars. Given that the earth has a mass `9` times and radius twice of the planet Mars. Escape speed on the surface of earth is `11.2 km s^(-1)`.

If the earth has mass 9 times and radius twice that of the planet Mars, calculate the minimum velocity required by a rocket to pull out of the gravitational force of Mars. Escape velocity on the surface of the earth in 11.2 km//s

If Earth has mass nine times and radius twice that of the planet Mars, calculate the velocity required by a rocket to pull out of the gravitational force of Mars. Take escape speed on surface of Earth to be 11.2km//s

Gravitational acceleration on the surface of a planet is (sqrt(6)//11) g, where g is the gravitational acceleration on the surface of the earth. The average mass density of the planet is 2/3 times that of the earth. If the escape speed on the surface of the earth is taken to be 11 km*s^(-1) , the escape speed on the surface of the planet in km*s^(-1) will be

Gravitational acceleration on the surface of a planet is (sqrt6)/(11)g. where g is the gravitational acceleration on the surface of the earth. The average mass density of the planet is (2)/(3) times that of the earth. If the escape speed on the surface of the earht is taken to be 11 kms^(-1) the escape speed on the surface of the planet in kms^(-1) will be

Graviational acceleration on the surface of plane fo (sqrt6)/(11)g. where g is the gracitational acceleration on the surface of the earth. The average mass density of the planet is (2)/(3) times that of the earth. If the escape speed on the surface of the earht is taken to be 11 kms^(-1) the escape speed on teh surface of the planet in kms^(-1) will be