यदि `sin theta+cos theta=x,` तो सिद्ध कीजिए कि `sin^(6)theta+cos^(6)theta=1-(3)/(4)(x^(2)-1)^2,x^(2) le 2`

Prove that sin^(6)theta+cos^(6)theta=1-(3)/(4)sin^(2)2 theta

If sin theta+cos theta=x then prove that sin^(6)theta+cos^(6)theta=(4-3*(x^(2)-1)^(2))/(4)

If sin theta+cos theta=x, Prove that :sin^(6)theta+cos^(6)theta=(4-3(x^(2)-1)^(2))/(4)

2(sin^(6) theta + cos^(6)theta) - 3(sin^(4)theta + cos^(4)theta)+ 1 = 0

If sin theta + cos theta = m, show that cos^(6)theta + sin^(6)theta = (4 - 3(m^(2) - 1)^(2))/(4) where m^(2) le 2 .

Prove that sin^(6)theta+cos^(6)theta=1-3sin^(2)theta cos^(2)theta

Prove that sin^(6)theta+cos^(6)theta=1-3sin^(2)theta.cos^(2)theta.

Prove that: sin^(6) theta + cos^(6) theta =1 - 3 sin^(2) theta cos^(2) theta

sin^(6)theta+cos^(6)theta+3sin^(2)theta cos^(2)theta=1