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" The differential equation; "ydx+x log(...

" The differential equation; "ydx+x log((y)/(x))dy-2xdy=0" is "

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Solve the differential equation ydx+ {xlog ((y)/(x))} dy-2x dy=0

Solve the differential equation: ydx + x log (y/x) dy-2xdy=0

Solve the differential equation 2y dx + 2x log ((y)/(x))dy - 4xdy = 0

Solve the following differential equation: ydx+x log((y)/(x))dy=2xdy

y dx + x log ((y)/(x))dy - 2xdy = 0

y dx + x log ((y)/(x))dy - 2xdy = 0

The general solution of the differential equation (ydx-xdy)/(x)=0 is

The general solution of the differential equation (ydx-xdy)/(y)=0 is :