With the usual notation in a `DeltaABC,|(1,1,1),(sin A,sin B,sin C),(sin^2 A,sin^2 B, sin^2 C)|=`

With the usual notation in DeltaABC det |(1,1,1),(sinA,sinB,sinC),(sin^(2)A,sin^(2)B,sin^(2)C)| assumes the value

det [[1,1,1sin A, sin B, sin Csin ^ (2) A, sin ^ (2) B, sin ^ (2) C]] =

With the usual notation in the triangle A B C [[ 1 , 1 , 1 ],[ sin A , sin B , sin C ],[ sin ^2 A , sin ^2 B , sin ^3 C ]] =

In DeltaABC,(sin 2A+ sin 2B+ sin 2C)/(sin A + sin B+ sin C)=

If A, B and C are the angles of a triangle and |(1,1,1),(1 + sin A,1 + sin B,1 + sin C),(sin A + sin^(2) A,sin B + sin^(2)B,sin C + sin^(2) C)|= 0 , then the triangle ABC is

If A, B and C are the angles of a triangle and |(1,1,1),(1 + sin A,1 + sin B,1 + sin C),(sin A + sin^(2) A,sin B + sin^(2)B,sin C + sin^(2) C)|= 0 , then the triangle ABC is

In any DeltaABC , sin A + sin B + sin C =

In any DeltaABC , sin A + sin B + sin C =

If A, B, C are the angles of a triangle, then the determinant Delta = |(sin 2 A,sin C,sin B),(sin C,sin 2B,sin A),(sin B,sin A,sin 2 C)| is equal to