" The solution of the equation "sin^(-1)x+sin^(-1)2x=(pi)/(3)" is "

Solve sin^(-1)x+sin^(-1)2x=(pi)/(3)

The number of solution (s) of the equation sin^(-1)(1-x)-2sin^(-1)x=(pi)/(2) is/are

Number of solutions of the equation,sin^(-1)(1-x)-4sin^(-1)(x)=(pi)/(2), is equal to

The solution of sin^(-1)x-sin^(-1)2x=pm(pi)/(3) is

The solution of sin^(-1)x-sin^(-1)2x=pm(pi)/(3) is

The solution of sin^(-1)x-sin^(-1)2x=pm(pi)/(3) is

Let alpha is the solution of equation sin^(-1)(2sin^(-1)(cos^(-1)(tan^(-1)x)))=0 and beta is the solution of equation sin^(-1)x+sin^(-1)x^(2)=(pi)/(2), then -

Solve sin^(-1)x + sin^(-1) 2x = (pi)/(3)