If `Delta=|(a_1,b_1,c_1),(a_2,b_2,c_2),(a_3,b_3,c_3)|` and `Delta_1=|(a_1+pb_1,b_1+qc_1,c_1+ra_1),(a_2+pb_2,b_2+qc^2,c^2+ra^2),(a_3+pb_3,b_3+qc_3,c_3+ra_3)|` then `Delta_1=`

If D=|(a_1,b_1,c_1),(a_2,b_2,c_2),(a_3,b_3,c_3)|andD'=|(a_1+pb_1,b_1+qc_1,c_1+ra_1),(a_2+pb_2,b_1+qc_2,c_2+ra_2),(a_3+pb_3,b_3+qc_3,c_3+ra_3)| , then :

Let D= |(a_1,b_1,c_1),(a_2,b_2,c_2),(a_3,b_3,c_3)|, D_1=|(a_1+pb_1, b_1+qc_1, c1+ra_1),(a_2+pb_2, b_2+qc_2, c_2+ra_2),(a_3+pb_3, b_3+qc_3, c_3+ra_3)| , then the value of (2010D-D_1)/D_1 is

Let D= |(a_1,b_1,c_1),(a_2,b_2,c_2),(a_3,b_3,c_3)|, D_1=|(a_1+pb_1, b_1+qc_1, c1+ra_1),(a_2+pb_2, b_2+qc_2, c_2+ra_2),(a_3+pb_3, b_3+qc_3, c_3+ra_3)| , then the value of (2010D-D_1)/D_1 is

If Delta=|(a_1,b_1,c_1),(a_2,b_2,c_2),(a_3,b_3,c_3)|, then the value of Delta_1=|(a_1+2b_1+3c_1,2c_1+3c_1,c_1),(a_2+2b_2+3c_2,2b_2+3c_2,c_2),(a_3+2b_3+ 3c_3,2b_3+3c_3,c_3)| is equal to

If Delta =|(a_1,b_1,c_1),(a_2,b_2,c_2),(a_3,b_3,c_3)| then the value of |(2a_1+3b_1+4c_1,b_1,c_1),(2a2+3b_2+4c_2,b_2,c_2),(2a_3+3b_3+4c_3,b_3,c_3)| is equal to

Suppose Delta = |(a_(1),b_(1),c_(1)),(a_(2),b_(2),c_(2)),(a_(3),b_(3),c_(3))|andDelta'=|(a_(1)+pb_(1),b_(1)+qc_(1),c_(1)+ra_(1)),(a_(2)+pb_(2),b_(2)+qc_(2),c_(2)+ra_(2)),(a_(3)+pb_(3),b_(3)+qc_(3),c_(3)+ra_(3))| then (i) Δ'=Δ (ii) Δ'=Δ(1−pqr) (iii) Δ'=Δ(1+P+q+r) (iv) Δ'=Δ(1+pqr)

If delta =|(a_1,b_1,c_1),(a_2,b_2,c_2),(a_3,b_3,c_3)| then the value of |(2a_1+3b_1+4c_1,b_1,c_1),(2a2+3b_2+4c_2,b_2,c_2),(2a_3+3b_3+4c_3,b_3,c_3)| is equal to

If A=[[a_1,b_1,c_1],[a_2,b_2,c_2],[a_3,b_3,c_3]] and B=[[ c_1,c_2,c_2],[a_1,a_2,a_3],[b_1,b_2,b_3]] then

suppose D= |{:(a_(1),,b_(1),,c_(1)),(a_(2),,b_(2),,c_(2)),(a_(3),,b_(3),,c_(3)):}| and Dprime= |{:(a_(1)+pb_(1),,b_(1)+qc_(1),,c_(1)+ra_(1)),(a_(2)+pb_(2),,b_(2)+qc_(2),,c_(2)+ra_(2)),(a_(3)+pb_(3),,b_(3)+qc_(3),,c_(3)+ra_(3)):}| . Then