If `a^2+b^2=1` t h e n ` (1+b+i a)/(1+b-i a)=` `1` b. `2` c. `b+i a` d. `a+i b`

If z(1+a)=b+i ca n da^2+b^2+c^2=1, then [(1+i z)//(1-i z)= A. (a+i b)/(1+c) B. (b-i c)/(1+a) C. (a+i c)/(1+b) D. none of these

If z(1+a)=b+i ca n da^2+b^2+c^2=1, then [(1+i z)//(1-i z)= A. (a+i b)/(1+c) B. (b-i c)/(1+a) C. (a+i c)/(1+b) D. none of these

If z(1+a)=b+i c and a^2+b^2+c^2=1, then [(1+i z)//(1-i z)= A. (a+i b)/(1+c) B. (b-i c)/(1+a) C. (a+i c)/(1+b) D. none of these

If A=[[a+i b, c+i d],[-c+i d, a-i b]] and a^2+b^2+c^2+d^2=1,t h e n ,A^(-1) is equal to a. [[a+i b,-c+i d],[c+i d, a-i b]] b. [[a-i b,-c-i d],[-c-i d, a+i b]] c. [[a+i b,-c-i d],[-c+i d, a-i b]] d. none of these

If A=[[a+i b, c+i d],[-c+i d, a-i b]] and a^2+b^2+c^2+d^2=1,t h e n ,A^(-1) is equal to a. [[a+i b,-c+i d],[c+i d, a-i b]] b. [[a-i b,-c-i d],[-c-i d, a+i b]] c. [[a+i b,-c-i d],[-c+i d, a-i b]] d. none of these

If A=[[a+i b, c+i d],[-c+i d, a-i b]]a n da^2+b^2+c^2+d^2=1,t h e nA^(-1) is equal to a. [[a+i b,-c+i d],[-c+i d, a-i b]] b. [[a-i b,-c-i d],[-c-i d, a+i b]] c. [[a+i b,-c-i d],[-c+i d, a-i b]] d. none of these

If a=1+i, then a^(2) equals 1-i b.2i .(1+i)(1-i) d.(i-1)

If A=[[a+i b, c+i d],[-c+i d, a-i b]]a n da^2+b^2+c^2+d^2=1,t h e nA^(-1) is equal to a.[[a+i b,-c+i d],[-c+i d, a-i b]] b. [[a-i b,-c-i d],[-c-i d, a+i b]] c. [[a+i b,-c-i d],[-c+i d, a-i b]] d. none of these

Let x_1, x_2, ,x_n be x_n observations. Let y_i=a x_i+b for i=1,2,...,n where a and b are constants. If the mean of x_i's is 48 and their standard deviation is 12, the mean of y_i 's is 55 and standard deviation of y_i's is 15, the values of a and b are (a) a=1. 25 ,b=-5 (b) a=-1. 25 ,b=5 (c) a=2. 5 ,b=-5 (d) a=2. 5 ,b=5

Let x_1, x_2, ,x_n be x_n observations. Let y_i=a x_i+b for i=1,2,...,n where a and b are constants. If the mean of x_i's is 48 and their standard deviation is 12, the mean of y_i 's is 55 and standard deviation of y_i's is 15, the values of a and b are (a) a=1. 25 ,b=-5 (b) a=-1. 25 ,b=5 (c) a=2. 5 ,b=-5 (d) a=2. 5 ,b=5