A balloon is going vertically upwards with a velocity of `10 m//s`. When it is `75 m` above the ground, a stone is gently relesed from it. The time taken by the stone to reach the ground is `(g=10 m//s^(2))`

A balloon is going vertically upward with a velocity of 15 ms^-1 . When it is at a height of 50 m above the ground a stone is gently dropped from it. The stone will reach the ground in time (take g = 10 ms^-2) :

A balloon rises with uniform velocity of 10 ms^(-1) . When the balloon is at a height of 75 m if a stone is dropped from it the time taken by it to reach the ground is

A balloon rises with uniform velocity of 10 ms^(-1) . When the balloon is at a height of 75 m if a stone is dropped from it the time taken by it to reach the ground is

A balloon starts rising from the ground with a constant acceleration of 1.25m//s^(2) . After 8 s, a stone is released from the balloon. Find the time taken by the stone to reach the ground. (Take g=10m//s^(2) )

A balloon starts rising from the ground with a constant acceleration of 1.25m//s^(2) . After 8 s, a stone is released from the balloon. Find the time taken by the stone to reach the ground. (Take g=10m//s^(2) )

A balloon is going upwards with a velocity of 20 m It releases a packet when it is at a height of 160 m from the ground. The time taken by the packet to reach the ground is

A balloon is going upwards with a constant velocity 15 m//s . When the ballooon is at 50 m height, a stone is dropped outside from the balloon. How long will stone take to reach at the ground? ("take " g=10 m//s^(2))

A balloon is going upwards with a constant velocity 15 m//s . When the ballooon is at 50 m height, a stone is dropped outside from the balloon. How long will stone take to reach at the ground? ("take " g=10 m//s^(2))