If the amplitude of two interfering light waves are not equal, then the intensity in the dark region formed in the interference pattern will be

If the ratio of the amplitudes of two interfering wave is 4:3, then the ratio of the maximumum and minimum intensities in the interference pattern is

If ratio of amplitude of two interferring source is 3 : 5 . Then ratio of intensity of maxima and minima in interference pattern will be:

The amplitude of two interfering waves are a and 2a respectively. The resultant amplitude in the condition of constructive interference will be:

The amplitude of two interfering waves are a and 2a respectively. The resultant amplitude in the condition of constructive interference will be:

The two interfering waves have intensities in the ratio 9 : 4 . The ratio of intensities of maxima and minima in the interference pattern will be

The amplitudes of two interfering waves are 4 cm and 3 cm respectively. If the resutant amplitude is 1 am then the interference becomes

Ratio of amplitude of interfering waves is 3:4 . Now ratio of their intensities will be

In a Young's double slit interference experiment, the ratio of intensity at the maxima and minima in the interference pattern is 25/9 . What will be the ratio of amplitudes of light emitted by the two slits?

Two coherent sources of light of intensity ratio n are employed in an interference experiment. The ratio of the intensities of the maxima and minima in the interference pattern is