" 99.4.हिन कीाजिए : "int(d theta)/(b cos theta+c sin theta)

int (sin theta + cos theta) * d theta

If sin theta=a/b cos theta=c/d then tan theta=

int(sin^(3)theta)/(sqrt(cos theta))d theta

int(d theta)/(sin theta cos^(3)theta) is equal to

int(sqrt(cos2 theta))/(sin theta)d theta=

int (cos^(4)theta )/("sin" theta)d theta

int (sin^(3) theta d theta)/sqrt cos theta

int (1 + cos theta) / (theta + sin theta) d theta

Integration using rigonometric identities : int(sin theta)/(cos3 theta)+(sin 3 theta)/(cos9 theta)+( sin9 theta)/(cos 27theta)d theta=...+c