`""_86^222Rn` goes through radioactive distintegrations by successive emissions of `alpha, alpha, beta, beta , alpha , beta " and " beta` particles. Then final nucleus is

alpha -particles and beta -particles

alpha + beta = 5 , alpha beta= 6 .find alpha - beta

The nucleus resulting from ""_(92)U^(238) after successive emission of two alpha and four beta -particles is

|(alpha,-beta,0),(0,alpha,beta),(beta,0,alpha)|=0 , then

A nucleus with atomic number Z (Z = 92) emits the following particles in a sequence alpha, beta^(-), alpha, alpha, beta^(-), beta^(+), alpha, beta^(-), alpha, beta^(+) . The atomic number of the resulting nucleus is

In a radioactive decay,the nucleus emits an alpha -particle followed by two beta -particles.Show that the final nucleus is an isotope of the original line.

Radioactive pollution is caused by alpha, beta, gamma particles.