Home
Class 12
PHYSICS
A particle is executing a linear S.H.M. ...

A particle is executing a linear S.H.M. and its differential equation is `(d^(2)x)/(dt^(2))+ alpha x=0`. Its time period of motion is

Promotional Banner

Similar Questions

Explore conceptually related problems

A particle executes simple harmonic motion according to equation 4(d^(2)x)/(dt^(2))+320x=0 . Its time period of oscillation is :-

A particle executes simple harmonic motion according to equation 4(d^(2)x)/(dt^(2))+320x=0 . Its time period of oscillation is :-

A particle executes simple harmonic motion according to equation 4(d^(2)x)/(dt^(2))+320x=0 . Its time period of oscillation is :-

If a simple harmonic motion is represented by (d^(2)x)/(dt^(2)) + alphax = 0 , its time period is :

If a simple harmonic motion is represented by (d^(2)x)/(dt^(2)) + alphax = 0 , its time period is :

If a simple harmonic motion is represented by (d^(2)x)/(dt^(2)) + alphax = 0 , its time period is :

The equation, (d^(2)x)/(dt^(2))+ax=0 , represents an SHM. Find its time period.

The differnetial equation of S.H.M is given by (d^2x)/(dt^2)+propx=0 . The frequency of motion is