A particle starts from origin at time t=0 and moves in positive x-direction. Its velocity v varies with times as `v = 10that(i)` cm/s. The distance covered by the particle in 8 s will be

At the moment t=0 particle leaves the origin and moves in the positive direction of the x-axis. Its velocity varies with time as v=10(1-t//5) . The dislpacement and distance in 8 second will be

A particle located at x = 0 at time t=0 starts moving along positive x-direction with velocity v that varies as v = asqrt(x) . The displacement of the particle varies with time as :

A particle located at x = 0 at time t = 0 , starts moving along with the positive x-direction with a velocity 'v' that varies as v = a sqrt(x) . The displacement of the particle varies with time as

A particle located at x = 0 at time t = 0 , starts moving along with the positive x-direction with a velocity 'v' that varies as v = a sqrt(x) . The displacement of the particle varies with time as

A particle located at x = 0 at time t = 0 , starts moving along with the positive x-direction with a velocity 'v' that varies as v = a sqrt(x) . The displacement of the particle varies with time as

A particle starts from the origin at time t = 0 and moves along the positive x-axis. The graph of velocity with respect to time is shown in figure. What is the position of the particle at time t = 5s ?

A particle starts from the origin at time t = 0 and moves along the positive x-axis. The graph of velocity with respect to time is shown in figure. What is the position of the particle at time t = 5s ?

A particle located at x = 0 at time t = 0, starts moving along the positive x-direction with a velocity that varies as v=psqrtx . The displacement of the particle varies with time as (where, p is constant)

A particle located at x = 0 at time t = 0, starts moving along the positive x-direction with a velocity that varies as v=psqrtx . The displacement of the particle varies with time as (where, p is constant)