We know that electric field (E ) at any point in space can be calculated using the relation
`vecE = - (deltaV)/(deltax)hati - (deltaV)/(deltay)hatj - (deltaV)/(deltaz)hatk`

if we know the variation of potential (V) at that point. Now let the electric potential in volt along the x-axis vary as `V = 2x^2`, where x is in meter. Its variation is as shown in figure
Draw the variation of electric field (E ) along the x-axis.

We know that electric field (E ) at any point in space can be calculated using the relation vecE = - (deltaV)/(deltax)hati - (deltaV)/(deltay)hatj - (deltaV)/(deltaz)hatk if we know the variation of potential (V) at that point. Now let the electric potential in volt along the x-axis vary as V = 2x^2 , where x is in meter. Its variation is as shown in figure Will the particle perform a simple harmonic motion? Also, find the time period of its oscillations.

We know that electric field (E ) at any point in space can be calculated using the relation vecE = - (deltaV)/(deltax)hati - (deltaV)/(deltay)hatj - (deltaV)/(deltaz)hatk if we know the variation of potential (V) at that point. Now let the electric potential in volt along the x-axis vary as V = 2x^2 , where x is in meter. Its variation is as shown in figure A charge particle of mass 10 mg and charge 2.5 muC is released from rest at x = 2 m . Find its velocity when it crosses origin.

We know that electric field (E ) at any point in space can be calculated using the relation vecE = - (deltaV)/(deltax)hati - (deltaV)/(deltay)hatj - (deltaV)/(deltaz)hatk if we know the variation of potential (V) at that point. Now let the electric potential in volt along the x-axis vary as V = 2x^2 , where x is in meter. Its variation is as shown in figure A charge particle of mass 10 mg and charge 2.5 muC is released from rest at x = 2 m . Find its velocity when it crosses origin.

The variation of electric potential for an electric field directed parallel to the x - axis is shown in (Fig. 3.110). Draw the variation of electric field strength with the x- axis. .

The variation of electric potential for an electric field directed parallel to the x - axis is shown in (Fig. 3.110). Draw the variation of electric field strength with the x- axis. .

The electric potential V at any point in space is given V = 20 x ^3 volt, where x is in meter. Calculate the electric intensity at point P (1, 0, 2).

In a certain region of space, variation of potential with distance from origin as we move along x-axis is given by V = 8 x^(2) + 2 , where x is the x-coordinate of a point in space. The magnitude of electric field at a point ( -4,0) is

In a certain region of space, variation of potential with distance from origin as we move along x-axis is given by V = 8 x^(2) + 2 , where x is the x-coordinate of a point in space. The magnitude of electric field at a point ( -4,0) is

In a certain region of space, variation of potential with distance from origin as we move along x-axis is given by V = 8 x^(2) + 2 , where x is the x-coordinate of a point in space. The magnitude of electric field at a point ( -4,0) is

the electric potential in the region of space is given by : V(x)=A+Bx+Cx^(2) where V is in volts, x is in meters and A,B,C are constants.Then,