An object is projected with velocity `vecv_(0) = 15hatj + 20hatj` . Considering x along horizontal axis and y along vertical axis. Find its velocity after 2s.

An object is projected with velocity vecv_(0) = 15hati + 20hatj . Considering x along horizontal axis and y along vertical axis. Find its velocity after 2s.

The velocity of an object at t =0 is vecv_(0) =- 4 hatj m/s . It moves in plane with constant acceleration veca = ( 3hati + 8 hatj) m//s^(2) . What is its velocity after 1 s?

The velocity of an object at t =0 is vecv_(0) =- 4 hatj m/s . It moves in plane with constant acceleration veca = ( 3hati + 8 hatj) m//s^(2) . What is its velocity after 1 s?

A body is projected with a velocity of 60 m/s at 30^(@) to horizontal (assume positive x-axis and positive y axis as horizontal and vertical directions, respectively, and take g=10m//s^(2) ).

The initial velocity of a projectile is (hati+2hatj)m//s , where hati and hatj are unit vectors along the horizontal and vertical directions respectively. Find out the locus of the projectile , taking g=10 m//s^2 .

A particle is projected with a velocity vecv=8hati+6hatj m//s . The time after which it will starts moving perpendicular to its initial direction of motions is

A projectile is given an initial velocity of (hati+2hatj)m/s , where hati is along the ground and hatj is along the vertical. If g=10m/s^-2 , the equation of its trajectory is