A particle performing S.H.M. about equilibrium position. Then the velocity of the particle is

The particle performing S.H.M., about mean position it has

A particle is performing SHM. At what distance from mean position, the velocity of the particle becomes half of the maximum velocity ?

A particle is performing a linear S.H.M. of period 24 s. The velocity of the particle is 6.28 m/s after 4 s after cros"sin"g the mean position. What is the amplitude of S.H.M. ?

A particle performing S.H.M. about their mean position with the equation of velocity is given by 4v^(2)=25-x^(2) , then the period of motion is

A particle performing S.H.M. starts horn mean position. The position of particle from its mean position where the difference of K E and P E is zero is (Take maximum displacement of particle is 8 m)

A particle performs linear S.H.M. At a particular instant, velocity of the particle is 'u' and acceleration is ' prop ' while at another instant, velocity is 'v' and acceleration ' beta ' (0ltpropltbeta) . The distance between the two position is

A particle performs linear S.H.M. At a particular instant, velocity of the particle is 'u' and acceleration is ' prop ' while at another instant, velocity is 'v' and acceleration ' beta ' (0ltpropltbeta) . The distance between the two position is

A particle performs linear S.H.M. At a particular instant, velocity of the particle is u and acceleration is alpha while at another instant, velocity is v and acceleration beta (0ltalphaltbeta) . The distance between the two position is

Assertion: Total energy of a particle executing S.H.M. · is maximum at mean position . Reason: The velocity of the particle executing S.H.M. is maximum at mean position.

Assertion: Total energy of a particle executing S.H.M. · is maximum at mean position . Reason: The velocity of the particle executing S.H.M. is maximum at mean position.