If `(a-b)^(2)+(a+b)^(2)=24`, then `a^(2)+b^(2)=`

If a-b = 5 and ab = 24, then a^2 + b^2

If a - b = 5 and ab = 24, then a^2 + b^2 =

If a + b = 6 and a^(2) - b^(2) = 24 , then a - b = 4 .

Factorise : (a+ b) ^(2) - 5( a^(2) - b^(2) ) - 24 (a-b)^(2)

If a+b=10, ab=24 then find a^2+b^2

Factorise the using the identity a ^(2) + 2 ab + b ^(2) = (a + b) ^(2) 2x ^(3) + 24 x ^(2) + 72 x

If AB=A and BA=B, where A and B are square matrices,then B^(2)=B and A^(2)=A (b) B^(2)!=B and A^(2)=A( c) A^(2)!=A,B^(2)=B (d) A^(2)!=A,B^(2)!=B