A simple harmonic oscillator has its displacement varying as x = 15 sin `(2pit+pi//4)` metre. Then its initial displacement is

The displacement equation of an oscillator is given by x = 5 sin (2pit+0.5pi)m . Then its time period and initial displacement are

The displacement of a simple harmonic oscillator is given by x = 4 cos (2pit+pi//4)m . Then velocity of the oscillator at t = 2 s is

A simple harmonic motion of a particle is represented by an equation x= 5 sin(4t -(pi)/(6)) , where x is its displacement. If its displacement is 3 unit then find its velocity.

A body executing linear simple harmonic motion has a velocity of 3 cm/s when its displacement is 4 cm and a velocity of 4 cm/s when its displacement is 3 cm. Then amplitude of oscillation with be

The acceleration of a simple harmonic oscillator is 1 m//s^(2) when its displacement from mean position is 0.5 m. Then its frequency of oscillation is

The displacement equation of a particle performing S.H.M. is x = 10 sin (2pit+(pi)/(6)) m. Then the initial displacement of a particle is