The displacement of a SHO is given by,
`y=0.4sin(10pit+pi//3)cos(10pit+pi//3)`
The ratio of maximum velocity to the maximum acceleration of the particle is

The displacement of a particle executing S.H.M from its mean position is given by x = 0.5 sin (10 pit +phi) cos (10pit +phi) . The ratio of the maximum velocity to the maximum acceleration of the body is given by

The displacement of a SHO is given by y = 2 sin (2pit+pi//4)m . The ratio of its initial displacement to maximum displacement is

The displacement of a body executing SHM is given by x=A sin (2pit+pi//3) . The firs time from t=0 when the velocity is maximum is

The displacemtent x (in cm ) of an oscillating body varies with time t as x=3cos(pit+(pi)/(4)) The magnittude of maximum acceleration of the particle in cm//s^(2) is

The displacement of a body executing SHM is given by x=Asin(2pit+pi//6) . The first time from t = 0 when the velocity is maximum is :

The displacement of a body executing SHM is given by x=lambdasin(2pit+pi//3) . The first time from t = 0 when the velocity is maximum is :

The displacement of a particl executing SHM is given by Y=10 sin (3t+pi//3)m and t is in seconds. The initial displacement and maximum velocity of the particle are respectively