Two simple harmonic motions are represented as `y_(1)=10 "sin" omega " and "y_(2)=5 "sin" wt +5 "cos" omega t`
The ration of the amplitudes of `y_(1) " and " y_(2)` is

Two simple harmonic motions are represented by y_(1)= 10 "sin" omega t " and " y_(2) =15 "cos" omega t . The phase difference between them is

Two simple harmonic motions are represented by y_(1)=5[sin2pit+sqrt(3)cos2pit] and y_(2)=5sin(2pit+(pi)/(4)) The ratio of their amplitudes is

Two simple harmonic motions are given by y _(1) = 5 sin ( omegat- pi //3). y_(2) = 5 ( sin omegat+ sqrt(3) cos omegat) . Ratio of their amplitudes is

Two simple harmonic motions are given by y _(1) = 5 sin ( omegat = pi //3). y_(2) = 5 ( sin omegat+ sqrt(3) cos omegat) . Ratio of their amplitudes is

Two simple harmonic motions are represented by y_(1)=5 [sin 2 pi t + sqrt(3)cos 2 pi t] and y_(2) = 5 sin (2pit+(pi)/(4)) The ratio of their amplitudes is

Two wave are represented by equation y_(1) = a sin omega t and y_(2) = a cos omega t the first wave :-

Two simple harmonic motions are represented by y_(1) = 10 sin"" (pi)/(4) (12t+1)" and " y_(2) = 5(sin"" 3pi t+ sqrt(3) cos 3pi t) . Find out the ratio of their amplitudes. What are the time period of two motions.

Two simple harmonic motions are represented by the equations. y_(1)=10"sin"(pi)/(4)(12t+1),y_(2)=5(sin3pt+sqrt(3)cos3pt) the ratio of their amplitudes is

Two simple harmonic motions are represented by the equations. y_(1)=10"sin"(pi)/(4)(12t+1),y_(2)=5(sin3pt+sqrt(3)cos3pt) the ratio of their amplitudes is