The displacement of a particle performing a S.H.M. is given by `x =12 "cos" (omega t + alpha) cm`. If at time t, the displacement of the particle is 6 cm, them the phase of the particle at that instant is

The displacement of a particle performing S.H.M. is given by x=10 "sin"(omega t+ alpha) metre. If the displacement of the particle is 5m, then the phase of S.H.M. is

The displacement of a particle in S.H.M is in opposite phase with

The displacement of a particle executing a S.H.M. is given by x= A "sin" omega t +A "cos" omega t . What is the amplitude of motion ?

The displacement of a particle performing a S.H.M is given by x=0.25 "cos" [8 pi t+(pi)/(3)] . The frequency of S.H.M. is

The displacement of a particle in S.H.M. is given by x = sinomegat+sqrt(3)cosomegatm . Then at t = 0 its displacement in metres is

The displacement of a particle in S.H.M. is given by x= B "sin" (omega t + alpha) . The initial position (at time t=0), of the particle is the initial phase angle if the angular frequency of the particle is pi rad//s ?

The displacement of a particle making S.H.M. is given by x=6cos(100t+(pi)/(4))m then the frequency is

The displacement of a particle executing S.H.M. is given by, y = 0.20 sin (100 t) cm. The maximum speed of the particle is