The equation of displacement of a particle performing a S.H.M. is x=0.25 "sin" (200 t) metre. What is the maximum velocity of the particle ?

The equation of displacement of particle performing S.H.M. is x = 0.25 sin (200 t). The maximum velocity is

The equation of displacement of particle performing S.H.M. is x = 0.25 sin (200 t). The maximum velocity is

If the displacement of a particle executing S.H.M. is given by x = 0.24 sin (400 t + 0.5)m, then the maximum velocity of the particle is

The displacement of a particle executing S.H.M. is given by, y = 0.20 sin (100 t) cm. The maximum speed of the particle is

The displacement of a particle executing S.H.M. is given by, y = 0.20 sin (100 t) cm. The maximum speed of the particle is

The displacement of a particle executing S.H.M. is given by y = 0.25 sin 200t cm. The maximum speed of the particle is

The displacement of a particle performing S.H.M. is given by x=10 "sin"(omega t+ alpha) metre. If the displacement of the particle is 5m, then the phase of S.H.M. is

The displacement of a particle performing SHM x= 3sin 2t+4 cos 2t . The amplitude and maximum velocity of a particle respectively are………….

The displacement of a particle performing S.H.M is x=A" "sin(omegat+prop) . The quantity prop is called