A particle moves in a circular path of radius R with an angualr velocity `omega=a-bt`, where a and b are positive constants and t is time. The magnitude of the acceleration of the particle after time `(2a)/(b)` is

A particle is moving along a circular path of radius 'r' with uniform angular velocity omega . Its angular acceleration is

A particle moving in a circular path of certain radius, with uniform angular velocity omega has an angular acceleration equal to :

A particles is moving on circular path of radius R with constant angular velocity omega . Its centripetal acceleration will be …... .

A particle moves from A to B in a circular path of radius R covering an angle theta as shown in figure. Find the ratio of magnitude of distance and magnitude of displacement of the particle.

The linear speed of a particle moving in a circle of radius R varies with time as v = v_0 - kt , where k is a positive constant. At what time the magnitudes of angular velocity and angular acceleration will be equal ?

The linear speed of a particle moving in a circle of radius R varies with time as v = v_0 - kt , where k is a positive constant. At what time the magnitudes of angular velocity and angular acceleration will be equal ?

A particle of mass m is moving in a circle of radius r. The centripetal acceleration (a_(c)) of the particle varies with the time according to the relation, a_(c)=Kt^(2) , where K is a positive constant and t is the time. The magnitude of the time rate of change of angular momentum of the particle about the centre of the circle is