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0.316 g of an organic compound, after he...

0.316 g of an organic compound, after heating with fuming nitric acid and barium nitrate crystals in a sealed tube gave 0.466 g of the precipitate of barium sulphate. Determine the percentage of sulphur in the compound.
(Atomic masses : Ba = 137, S = 32, O = 16, C = 12, H = 1).

Text Solution

Verified by Experts

Mass of the substance taken = 0.316 g
Mass of `BaSO_(4)` formed = 0.466 g
Molecular mass of `BaSO_(4) = 137 + 32 + 64 = 233`
Then, mass of S in 0.466 g of `BaSO_(4)`
`=(0.466xx32)/(233)g`
Percentage of S in compound
`=(0.466xx32xx100)/(233xx0.316)`
= 20.25
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