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0.15 g of iodoform gave 0.2682 g of AgI....

0.15 g of iodoform gave 0.2682 g of AgI. Calculate the percentage of iodine.

Text Solution

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Weight of compound = 0.15 g
Weight of silver iodide = 0.2682 g
Molecular weight of silver iodide `= 108 + 127 = 235`
235 g of silver iodide contains 127 g of iodine
0.2682 g of AgI contains `=(127xx0.2682)/(235)`
`=0.144 g` iodine
0.15 g of compound contains 0.144 g of iodine
100 g of compound contains `=(100xx0.1449)/(0.15)=96.6g`
`therefore" Percentage of iodine"=96.6`
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