The motion of a particle executing simple harmonic motion is described by the displacement function,
`x(t)=Acos(omegat+phi)`.
If the initial (t = 0) position of the particle is 1 cm and its initial velocity is `omega` cm/s, what are its amplitude and initial phase angle ? The angular frequency of the particle is `pi s^(-1)`. If instead of the cosine function, we choose the sine function to describe the SHM : `x = B sin (omegat + alpha)`, what are the amplitude and initial phase of the particle with the above initial conditions.

Explanation

`A=sqrt2cm,phi=7pi//4,B=sqrt2cm,a=pi//4`