A simple pendulum of length l and having a bob of mass M is suspended in a car. The car is moving on a circular track of radius R with a uniform speed v. If the pendulum makes small oscillations in a radial direction about its equilibrium position, what will be its time period ?

Explanation

`T=2pisqrt(l/(sqrt(g^(2)+v^(4)//R^(2))))` Hint: Effective acceleration due to gravity will get reduced due to radial acceleration `v^(2)//R` acting in the horizontal plane.