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As you have learnt in the text, a geosta...

As you have learnt in the text, a geostationary satellite orbits the earth at a height of nearly 36,000 km from the surface of the earth. What is the potential due to earth’s gravity at the site of this satellite ? (Take the potential energy at infinity to be zero). Mass of the earth `= 6.0 xx 10^(24) kg." radius" = 6400`km .

Text Solution

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`-9.4 xx 10^(6)` J/kg
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As you have learnt in the text ,a geostationary satellite orbits the earth at a height of nearly 36000 km from the surface of the earth. What is the potential due to earth's gravity at the site of this satellite? (Take the potential energy at infinity to be zero.) Mass of the earth= 6.0xx10^(24)kg , radius =6400 km.

What is the time period of satellite near the earth's surface? (neglect height of the orbit of satellite from the surface of the earth)?

Knowledge Check

  • A geostationary satellite is orbiting the earth at a height of 5R above the surface of the earth R being the radius of the earth the time period of another satellite in hours at a height 2R from the surface of the earth is

    A
    5
    B
    10
    C
    `6sqrt2`
    D
    `6/(sqrt2)`
  • A satellite of mass m is revolving around the earth at a height x above the surface of the earth. The radius of the earth is R. If the acceleration due to gravity is g, the orbital speed of the satellite will be

    A
    gx
    B
    `(gR)/(R-x)`
    C
    `(gR^2)/(R+x)`
    D
    `((gR^2)/(R+x))^(1//2)`
  • The ratio of energy required to raise satellite upto a height R (radius of earth) from the surface of earth to that required to put it into orbit at that height is

    A
    1:1
    B
    8:1
    C
    4:1
    D
    2:1
  • Similar Questions

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    A satellite orbits the earth at a height of 400 km above the surface. How much energy must be expended to rocket the satellite out of the earth’s gravitational influence? Mass of the satellite = 200 kg, mass of the earth = 6.0 ×x 10^(24) kg, radius of the earth = 6.4 xx 10^(6) m , G = 6.67 xx 10^(-11) N m^(2)) kg^(-2) .

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