(tan x+sec x-1)/(tan x-sec x+1)=(1+sin x)/(cos x)

int(tan x+sec x-1)/(tan x-sec x+1)dx

If tan y=(tan x+sec x-1)/(tan x-sec x+1) show that (dy)/(dx)=(1)/(2)

If tan y = (tan x+sec x-1)/(tanx -sec x+1) show that (dy)/(dx) = 1/2

If tan y=(tan x+sec x-1)/(tan x-sec x+1), " show that, " (dy)/(dx)=(1)/(2) .

If y=(sec x+tan x-1)/(tan x-sec x+1), find (dy)/(dx)]_(x=pi/4)

If y=(sin x)^(tan x), then (dy)/(dx)= (a) (sin x)^(tan x)(1+sec^(2)x log sin x)(b)tan x(sin x)^(tan x-1)cos x(c)(sin x)^(tan x)(d)sec^(2)x log sin x tan x(sin x)^(tan x-1)

Range of f(x)=(sec x+tan x-1)/(tan x-sec x+1)x in(0,(pi)/(2))

(tan 2x)/(1+ sec 2x) = tan x