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Two angles of a triangle are 1/2 radian...

Two angles of a triangle are `1/2` radian and `1/3` radian. The measure of the third angle in degree (taking `pi` = `22/7`)

A

`132 "" (1)/(11)""^(@)`

B

`132"" (2)/(11)""^(@)`

C

`132"" (3)/(11)""^(@)`

D

`132^(@)`

Text Solution

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The correct Answer is:
To find the measure of the third angle in a triangle when two angles are given in radians, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Angles**: The two angles of the triangle are: - Angle A = \( \frac{1}{2} \) radian - Angle B = \( \frac{1}{3} \) radian 2. **Convert Radians to Degrees**: We know that \( 1 \) radian = \( \frac{180}{\pi} \) degrees. We will use \( \pi = \frac{22}{7} \) as given in the problem. - For Angle A: \[ A_{degrees} = \frac{1}{2} \times \frac{180}{\pi} = \frac{1}{2} \times \frac{180 \times 7}{22} = \frac{90 \times 7}{22} = \frac{630}{22} = \frac{315}{11} \text{ degrees} \] - For Angle B: \[ B_{degrees} = \frac{1}{3} \times \frac{180}{\pi} = \frac{1}{3} \times \frac{180 \times 7}{22} = \frac{60 \times 7}{22} = \frac{420}{22} = \frac{210}{11} \text{ degrees} \] 3. **Calculate the Third Angle**: The sum of the angles in a triangle is \( 180 \) degrees. Let the third angle be \( C \). \[ A_{degrees} + B_{degrees} + C = 180 \] \[ \frac{315}{11} + \frac{210}{11} + C = 180 \] \[ \frac{525}{11} + C = 180 \] \[ C = 180 - \frac{525}{11} \] To perform this subtraction, convert \( 180 \) into a fraction with a denominator of \( 11 \): \[ 180 = \frac{180 \times 11}{11} = \frac{1980}{11} \] Now, substituting back: \[ C = \frac{1980}{11} - \frac{525}{11} = \frac{1980 - 525}{11} = \frac{1455}{11} \text{ degrees} \] 4. **Final Calculation**: Now, we can simplify \( \frac{1455}{11} \): \[ C = 132 \frac{3}{11} \text{ degrees} \] ### Conclusion: The measure of the third angle in degrees is \( 132 \frac{3}{11} \) degrees. ---
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