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A shopkeeper cheats to the extent of 20%...

A shopkeeper cheats to the extent of `20%` while buying as well as selling, by using false weights. His total gain is

A

20

B

25

C

44

D

34

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of the shopkeeper's total gain when cheating by 20% while buying and selling, we can break it down step by step. ### Step-by-Step Solution: 1. **Understanding the Cheating Percentage**: - The shopkeeper cheats by 20% both while buying and selling. This means that when he claims to buy or sell a certain quantity, he actually manipulates the quantity by 20%. 2. **Buying Process**: - Let’s assume the cost price (CP) of 1 kg of goods is ₹1. - When the shopkeeper buys, he cheats by 20%. This means he pays for 80% of the actual quantity he receives. - If he claims to buy 5 kg, he actually receives: \[ \text{Actual quantity bought} = \frac{5 \text{ kg}}{0.8} = 6.25 \text{ kg} \] - Thus, he pays ₹5 for 6.25 kg of goods. 3. **Selling Process**: - When selling, he also cheats by 20%. This means he sells only 80% of the quantity he claims. - If he claims to sell 5 kg, he actually sells: \[ \text{Actual quantity sold} = 5 \text{ kg} \times 0.8 = 4 \text{ kg} \] - If he sells this 5 kg at a price of ₹1 per kg, he receives ₹5 for 4 kg of goods. 4. **Calculating Total Gain**: - The total cost price for 6.25 kg is ₹5. - The total selling price for 5 kg is ₹5. - However, he actually sold 5 kg while he bought 6.25 kg. So, the effective gain can be calculated as: \[ \text{Total Gain} = \text{Selling Price} - \text{Cost Price} = ₹5 - ₹5 = ₹0 \] - But, since he sold 5 kg while he actually had 6.25 kg, we need to calculate the effective gain percentage: \[ \text{Effective Gain} = \left(\frac{\text{Selling Price} - \text{Cost Price}}{\text{Cost Price}}\right) \times 100 \] - Here, the effective gain is actually calculated based on the total quantity he sold versus the total quantity he bought. 5. **Final Calculation**: - The effective gain percentage can be calculated as: \[ \text{Total Gain Percentage} = \left(\frac{(1.25 \text{ kg})}{(5 \text{ kg})}\right) \times 100 = 25\% \] - Therefore, the total gain percentage is 44%. ### Conclusion: The total gain of the shopkeeper is **44%**.
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