From a uniform disc of radius R, an equilibatered triangle of side `sqrt3R` is cut as shown. The new position of centre of mass is:

From a uniform disc of radius R, an equilateral triangle of side sqrt(3)R is cut as shown in the figure. The new position of centre of mass is :

From a uniform disc of radius R, an equilateral triangle of side sqrt(3)R is cut as shown in the figure. The new position of centre of mass is :

From a uniform disc of radius R, a small disc of radius (R)/(2) is cut and removed as shown in the diagram. Find the center of mass of the remaining portion of the disc.

From a uniform disc of radius R , a circular section of radius R//2 is cut out. The centre of the hole is at R//2 from the centre of the original disc. Locate the centre of mass of the resulating flat body.

From a uniform disc of radius R , a circular section of radius R//2 is cut out. The centre of the hole is at R//2 from the centre of the original disc. Locate the centre of mass of the resulting flat body.

From a uniform disc of radius R, a circular disc of radius R/2 is cut out. The centre of the hole is at R/2 from the centre of original disc. Locate the centre of gravity of the resultant flat body.