If f (x) ` ae^(|x|)+b |x|^(2) ,a ,b in ` R and f(x) is differentiable at x =0 ,then

If f (x) = ae^(|x|)+b|x|^(2); a","b epsilon R and f(x) is differentiable at x=0.Then ,a and b are

If f(x)=a|sin x|+be^(|x|)+c|x|^(3) and if f(x) is differentiable at x=0, then a=b=c=0( b) a=0,quad b=0;quad c in R(c)b=c=0,quad a in R(d)c=0,quad a=0,quad b in R

If f(x)=a|sinx|+b\ e^(|x|)+c\ |x|^3 and if f(x) is differentiable at x=0 , then a=b=c=0 (b) a=0,\ \ b=0;\ \ c in R (c) b=c=0,\ \ a in R (d) c=0,\ \ a=0,\ \ b in R

Let f : R to R be a function such that f(x+y) = f(x)+f(y),Aax, y in R. If f (x) is differentiable at x = 0, then

Let f : R rarr R satisfying |f(x)|le x^(2), AA x in R , then show that f(x) is differentiable at x = 0.

Let f : R rarr R satisfying |f(x)|le x^(2), AA x in R , then show that f(x) is differentiable at x = 0.

Let f : R rarr R satisfying |f(x)|le x^(2), AA x in R , then show that f(x) is differentiable at x = 0.

A function f:R rarr R satisfies the equation f(x+y)=f(x)f(y) for allx,y in R and f(x)!=0 for all x in R .If f(x) is differentiable at x=0 .If f(x)=2, then prove that f'(x)=2f(x) .

If a function f(x) is defined as f(x) = {{:(-x",",x lt 0),(x^(2)",",0 le x le 1),(x^(2)-x + 1",",x gt 1):} then a. f(x) is differentiable at x = 0 and x = 1 b. f(x) is differentiable at x = 0 but not at x = 1 c. f(x) is not differentiable at x = 1 but not at x = 0 d. f(x) is not differentiable at x = 0 and x = 1