The distance covered by a particle in time (10.0 + 0.3)s is (50.0 + 0.2)m. The percentage error in speed of the body will be

The displacement covered by a body in time (5.0 +- 0.6) s is ( 40.4 +- 0.4 ) m . Calculate the speed of the body . Also determine the percentage error in the speed.

The distance travelled by a particle in time t is given by s = (2.5 t^(2)) m. Find (a) the average speed of the partion during time 0 to 0.5 s and (b) the instantaneous speed at t = 5.0s.

The distance travelled by a particle in time t is given by s=(2.5m/s^2)t^2 . Find a. the average speed of the particle during the time 0 5.0 s, and b. the instantaneous speed ast t=5.0 is

The resistance R= (V)/(I) , where V= (100+-5.0) V and I=(10+-0.2)A . Find the percentage error in R .

A particle moves along x-axis and its acceleration at any time t is a = 2 sin ( pit ), where t is in seconds and a is in m/ s^2 . The initial velocity of particle (at time t = 0) is u = 0. Q. Then the distance travelled (in meters) by the particle from time t = 0 to t = 1 s will be :

A particle moving in a straight line covers half the distance with speed of 3 m//s . The other half of the distance is covered in two equal time intervals with speed of 4.5 m//s and 7.5 m//s respectively. The average speed of the particle during this motion is :

A body travels uniformly a distance of (13.8+-0.2)m in a time (4.0+-0.3) see the velocity of body and/or percentage of error in velocity is:

A body travels unifromly a distance of (20.0 +- 0.2)m in time (4.0 +- 0.4)s . The velocity of the body is

The change in the velocity of a body is (12.5pm 0.2)m//s in a time (5.0pm0.3)s. Find the average acceleration of the body within error limits.