In a rectangle PQRS ,the coordinates of P and Q are (1,3) and (2,6) respectively and some diameter of the circumscribing circle of PQRS has the equation 3x-y+2=0. Then the area of the rectangle is

In a recatngle ABCD, the coordinates of A and B are (1, 2) and (3, 6) respectively and some diameter of the circumscribiling circle of ABCD has equation 2x-y+4=0 . Then the area of the rectangle is -

In a triangle PQR , the co-ordinates of the points P and Q are ( -2,4) and ( 4,-2) respectively. If the equation of the perpendicular bisector of PR is 2x - y+2=0 , then the centre of the circumcircle of the Delta PQR is :

The equation of one side of a rectangle is 3x-4y-10=0 and the coordinates of two of its vertices are (-2, 1) and (2, 4) . Find the area of the rectangle and the equation of that diagonal of the rectangle which passes through the point (2, 4) .

The foot of the normal from the point (1,2) to a circle is (3,4) and a diameter of the circle has the equation 2x+y+5=0 ,then the equation of the circle is

Consider a triangle PQR with coordinates of its vertices as P(-8,5), Q(-15, -19), and R (1, -7). The bisector of the interior angle of P has the equation which can be written in the form ax+2y+c=0. The distance between the orthocenter and the circumcenter of triangle PQR is

If ABCD be a rectangle and P, Q, R, S be the mid-points of AB, BC, CD and DA respectively, then the area of the quadrilateral PQRS is equal to

The coordinates of the vertices P,Q and R of a triangle PQR are (1,-1,1), (3,-2,2) and (0,2,6) respectively. If angleRQP=theta , then what is angle PRQ equal to ?

The coordinates of the vertices P,Q and R of a triangle PQR are (1,-1,1),(3,-2,2) and (0,2,6) respectively. If angleRQP=theta , then what is anglePRQ equal to ?