If `A=[[1,3,4],[2,1,2],[5,1,1]]`, find `A^(-1)`. Hence solve the system of equations : `x+3y+4z=8, 2x+y+2z=5` and `5x+y+z=7`

If A=[[2,3,4],[1,-1,0],[0,1,2]] , find A^(-1) . Hence, solve the system of equations x-y=3, 2x+3y+4z=17, y+2z=7

If A=[{:(1,1,1),(1,0,2),(3,1,1):}] , find A^(-1) . Hence, solve the system of equations : x+y+z=6 , x+2z=7 , 3x+y+z=12

The system of equations x+2y-4z=3,2x-3y+2z=5 and x -12y +16z =1 has

If A=[{:(3,1,2),(3,2,-3),(2,0,-1):}] , find A^(-1) . Hence, solve the system of equations : 3x+3y+2z=1 , x+2y=4 , 2x-3y-z=5

If A=[[1,-1,12,1,-31,1,1]], find A^(-1) and hence solve the system of linear equation.x+2y+z=4,-x+y+z=0,x-3y+z=2

If matrix A=[[2,1,-3],[3,2,1],[1,2,-1]] . Find A^(-1) and hence solve the system of equation 2x+y–3z=13, 3x+2y+z=4, x+2y-z=8

Solve the system of equations by cramer's rule: 3x+3y-4z=2 , 5x-y=4 and 8x+2y-3z=7

If A=((2,-3,5),(3,2,-4),(1,1,-2)) find A^(-1). Use it to solve the system of equations 2x-3y+5z=11 , 3x+2y-4z=-5 and x+y-2z=-3

If matrix A=[[2,3,1],[1,2,2],[-3,1,-1]] Find A^(-1) and hence solve the system of equation 2x+y-3z=13,3x+2y+z=4,x+2y-z=8

If A=[[3,2,1],[4,-1,2],[7,3,-3]] then find A^(-1) and hence solve the following system of equations : 3x+ 4y+7z= 14, 2x-y+ 3z= 4 and x+ 2y-32= 0.