`tan(A+B)=(tan A+tan B)/(1-tan A tan B)`

By using above basic addition/ subtraction formulae, prove that (i) tan (A+B)=(tan A+tan B)/(1-tan A tan B) , (ii) tan (A-B)=(tan A-tanB)/(1+tan A tan B) (iii) sin2theta=2sintheta costheta , (iv) cos2theta=cos^(2)theta=1-2sin^(2)theta=2cos^(2)theta-1 (v) tan 2theta=(2 tan theta)/(1-tan^(2) theta)

Prove that (tan (AB) + tan B) / (1-tan (AB) tan B) = tan A

If A+B+C=pi, prove that (tan A)/(tan B tan C)+(tan B)/(tan Atan C)+(tan C)/(tan A tan B)=tan A+tan B+tan C-2cot A-2cot B-2cot C

Prove that tan(A+B+C)=(tan A+tan B+tan C-tan A tan B tan C)/(1-tan A tan B-tan B tan C-tan C tan A)

(tan A+tan B-tan C+tan A tan B tan C)/(1-tan A tan B+tan B tan C+tan C tan A)

if A+B=135^(@) then (tan A.tan B)/((1+tan A)*(1+tan B))=

If sin A = (3)/(5) and cos B = (12)/(13) . Then the value of (tan A - tan B)/(1 + tan A tan B) is equal to

Prove that (tan A-tan B)^(2)+(1+tan A tan B)^(2)=sec^(2)A sec^(2)B

(tan A + tan B) / (tan (A + B)) + (tan A-tan B) / (tan (AB)) =