The foot of perpendicular drawn from the point `(-2,-1,-3)` to the plane is: `(1,-3,3)` Find the vector equation of that plane.

Foot of perpendicular drawn from a point P(-2, 3, 5) on the YZ-plane is

If the foot of the perpendicular drawn from the point (0,0,0) to the plane is (4,-2,-5) then the equation of the plane is . . .

The foot of the perpendicular drawn from the origin to the plane x+y+z=3 is

The coordinate of the foot of the perpendicular drawn from the origin to a plane are (12, -4, 3). Find the equation of the plane.

The foot of the perpendicular from the point P(1,3,4) to the plane 2x-y+z+3=0 is

Foot of perpendicular drawn from the origin to the plane 2x-3y+4z=29 is

The foot of the perpendicular drawn from the origin O to a plane is N(12,-4,-3). Find the equation of the plane in cartesian form and vector form.

The foot of perpendicular drawn from the origin to the plane is (4,-2,-5). Find the equation of the plane.

The coordinates of the foot of a perpendicular drawn from the origin to the plane are (2, 3, 1). Find the equation of the plane in vector form.

The foot of the perpendicular drawn from the origin to a plane is (1,2,-3). Find the equation of the plane.or If O is the origin and the coordinates of P is (1,2,-3), then find the equation of the plane passing through P and perpendicular to OP.