Ionic product of water is `10^(-12)` ,pH of water is

if ionic product of water is K_w=10^(-16) at 4^@C , then a solution with pH =7.5 at 4^@C will

Ionic product of water (K_(w) is 10^(-14)) at 25^(@)C . What is the dissociation constant of water and auto protonation constatn of water?

If the ionic product of water is 1.96 xx 10^(-14) at 35^(0)C ,What is the value at 10^(0)C

The ionic product of water at 25^@C is 10^(-14) its ionic product at 90^@C will be

Ionic product of water at 310 K is 2.7xx10^(-14) . What is the pH of netural water at this temperature?