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A tube 1 cm^2 in cross = section is atta...

A tube `1 cm^2` in cross = section is attached to the top of a vessel 1 cm high and of cross - section 100 `cm^2` Water is poured into the system filling it to a depth of 100 cm above the bottom of the vessel as shown in fig. Take `g = ms^I(-2)` Now.

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A tube 1 cm^2 in cross- section is attached to the top of a vessel 1 cm high and of cross - section 100 cm^2 Water is poured into the system filling it to a depth of 100 cm above the bottom of the vessel as shown in fig. Take g =10 ms^(-2) .

A tube 1 cm^2 in cross- section is attached to the top of a vessel 1 cm high and of cross - section 100 cm^2 Water is poured into the system filling it to a depth of 100 cm above the bottom of the vessel as shown in fig. Take g =10 ms^(-2) .

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A cylindrical vessel open at the top is 20cm high and 10 cm in diameter. A circular hole of cross-sectional area 1cm^(2) is cut at the centre of the bottom of the vessel. Water flows from a tube above it into the vessel at the rate of 10^(2)cm^(3)//s . The height of water in the vessel under steady state is (Take g=10m//s^(2)) .

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The area of base of a cylindrical vessel is 300 cm^(2) . Water ("density"=1000 kg m^(-3)) is poured into it up to a depth of 6 cm. Calculate : (a) the pressure and (b) the thrust of water on the base. (g=10ms^(-2)) .