`y^(2)=10x`

The length of the intercept that a circle x^(2)+y^(2)+10 x-6 y+9=0 makes on the x -axis is

Find the square root of the expressions (x^(2))/(y^(2))-10(x)/(y)+27-10(y)/(x)+(y^(2))/(x^(2))

If a x^(2)+6 x y+b y^(2)-10 x+10 y-6=0 represents a pair of perpendicular lines, then |a|=

Find the coordinates of the focus, axis of the parabola, the equation of the directrix and the length of the latus rectum. y^2=10 x

Find the coordinates of the focus, axis of the parabola, the equation of the directrix and the length of the latus rectum y^2=10 x

Find the length of latus rectum of the parabola y^(2) = - 10 x

Find the polar of (1,-2) with respect of x^(2) + y^(2) - 10 x - 10y + 25 = 0